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A bag contains 4 red, 2 blue, 6 green, and 8 white marbles. What is the probability of selecting a white marble at random from this bag, not replacing the marble, and then selecting another white marble? Round your answer to the nearest tenth of a percent if necessary.

a. 14%

b. 14.7%

c. 16%

d. 16.8%

 Mar 26, 2018

Best Answer 

 #1
avatar+442 
+4

Being that there is 4 red, 2 blue, 6 green, 8 white, that means there is 20 marbles, with 8 success, 8/20. Since the marble is not replaced, that drops it to 7/19 for the second pull. Multiply these together and you get 14.7%.

 

(8/20)*(7/19)=.147

.147*100=14.7

 Mar 26, 2018
 #1
avatar+442 
+4
Best Answer

Being that there is 4 red, 2 blue, 6 green, 8 white, that means there is 20 marbles, with 8 success, 8/20. Since the marble is not replaced, that drops it to 7/19 for the second pull. Multiply these together and you get 14.7%.

 

(8/20)*(7/19)=.147

.147*100=14.7

DerpofTheAbyss Mar 26, 2018

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