A bag contains 4 red marbles and 6 blue marbles. Three marbles are selected at random without replacement. What is the probability that at least one of the marbles selected is red?
+130511 The probability of at least one red one is...... 1 - P(no red selected). In essence, we're just counting the number of possible sets of green marbles only divided by the number of total possible sets and subtracting this result from 1.
So we have......
1 - C(6,3) / C(10, 3) = 5/6 or about 83.333%
+130511 The probability of at least one red one is...... 1 - P(no red selected). In essence, we're just counting the number of possible sets of green marbles only divided by the number of total possible sets and subtracting this result from 1.
So we have......
1 - C(6,3) / C(10, 3) = 5/6 or about 83.333%
