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A bag of peanuts in their shells contains 178 peanuts. 78 of the shells contain one peanut, 95 of the shells contain two peanuts, and the rest contain three peanuts. Of the shells with one peanut, 19 of them are cracked. Of the shells with two peanuts, 25 of them are cracked. None of the shells with three peanuts are cracked. One peanut shell is randomly selected from the bag. What is the probability the shell is cracked?

 Feb 20, 2020
 #1
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We have  178  peanuts.....

 

We   could either  choose  one of  the  19 of one-shelled peanuts  that  were cracked  or  we could choose  one of the 25 two-shelled  peanuts  that were cracked

 

So....

 

P ( chhosing  one of the 19 cracked  one-shelled peanuts  or 25 of the 2 cracked two-shelled peanuts )  =

 

19/ 178   +  25  /178   =

 

44  / 178   =

 

22 / 89   ≈  24.7 % 

 

 

 

cool cool cool

 Feb 20, 2020

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