A baker sold 33 loaves of bread in the morning. In the afternoon, he sold 60% of the remainder. As a result, the number of loaves of bread left became 1/8 of the number of bread he had at first. How many loaves of bread did the baker have at first?
+37084 Original number = 'x'
(x-33) #left after morning sales
.4(x-33) = # left after afternoon sales = 1/8x
.4x - 1/8x =13.2
x=48 loaves at start
+39 Say that the number of loaves of bread is N.
Morning sales are M = 33
Afternoon sales are A = 0.6 * (N - M)
And the rest is R = 1/8 * N
M + A + R = N
\(33 + 0.6*(N-33)+{1\over{8}}*N=N\)
\(33 + 0.6N-19.8+0.125N=N\)
\(13.2+0.725N=N\)
\(13.2=0.275N\)
\(N=13.2/0.275=48\)
Let's check: 33 sales leaves 15 loaves.
60% of 15 is 9 which leaves 6 loaves.
6 times 8 equals 48.
