+0  
 
0
887
1
avatar

A ball is thrown from an initial height of 3 meters with an initial upward velocity of 20m/s. The ball's height (in meters) after seconds is given by the following h=3+20t-5t^2. Find all values of for which the ball's height is 13 meters.

 Feb 15, 2021
 #1
avatar+36915 
+1

h=3+20t-5t^2.       looking for h = 13

13=3+20t-5t^2      re-arrange a bit

-5t2 +20t -10 = 0         divide by -5

t2 -4t +2 = 0    use Quadratic Formula     

 

a = 1      b = -4        c = 2

\(t= {-4 \pm \sqrt{(-4)^2-4(1)(2)} \over 2(1)}\)

 Feb 15, 2021

1 Online Users

avatar