a baseball leaves a bat with a speed of 44 m/s and at an angle of 30 above the horizontal. a 5 m high fence is located at a distance of 132

We need to find out how long it takes the ball to reach the fence....so we have :

132 = 44cos(30)*t    simplify

132 = 44 [√(3) / 2] * t  =

132 = 22√(3) *t            divide both sides by 22√(3)

132/22√(3) = t = 3.46 sec to travel to the fence

And the height ( y ) at that point is given by:

y = 44(3.46)sin(30) - 4.9(3.46)^2 + 1 = about 18.46 m

So....the ball clears the fence by  (18.46 - 5)m = 13.46m

[ Alan, could you make sure this one is correct ??? ]

[Thanks to Dragonlance for pointing out my earlier error ....!!!]

CPhill don’t you need to add the 1m above ground into the answer?

Ah.....thanks, Dragonlance.....I'll make the correction!!!!!

Yes, that's the right approach.  I got a slightly different numerical answer (13.37m), but that's primarily because I used more decimal places for t (3.4641 s).

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