a basic but confounding question of trig

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How to solve this: sin 240 x sec (-45)-tan(-30) x csc(-315)

math

sradle Aug 18, 2014

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Best Answer

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sin 240 x sec (-45)-tan(-30) x csc(-315)=

[-√(3)/2]*[√2] - [-1/√(3)]*[√2] =

[-√6/2] + [√2/√3] =

[-√6/2] + [√6/3] =

[-3√6]/6 + [2√6]/6 =

-√6 / 6

CPhill Aug 18, 2014

1⁺⁰ Answers

+130511

+5

Best Answer

sin 240 x sec (-45)-tan(-30) x csc(-315)=

[-√(3)/2]*[√2] - [-1/√(3)]*[√2] =

[-√6/2] + [√2/√3] =

[-√6/2] + [√6/3] =

[-3√6]/6 + [2√6]/6 =

-√6 / 6

CPhill Aug 18, 2014

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