A basketball has a circumference of 29.5 inches. Using 3.14 as an approximation for π, what is the basketball's volume to the nearest cubic

Actually, the volume of a sphere is $$(4/3)pi*r^3$$ not $$(4/3)*pi*r^2$$. So $$(4/3)*pi*(1475/314)^3$$ is about 434 cubic inches.

To first find the volume of the sphere, you need to first find the radius. To find this, you take the circumference of 29.5 inches and divide by pi to get the diameter.

$${\mathtt{C}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{D}}$$

$${\frac{{\mathtt{29.5}}}{{\mathtt{3.14}}}} = {\frac{{\mathtt{1\,475}}}{{\mathtt{157}}}} = {\mathtt{9.394\: \!904\: \!458\: \!598\: \!726\: \!1}}$$

Then divide the diameter by 2 to get the radius.

$${\frac{\left({\frac{{\mathtt{29.5}}}{{\mathtt{3.14}}}}\right)}{{\mathtt{2}}}} = {\frac{{\mathtt{1\,475}}}{{\mathtt{314}}}} = {\mathtt{4.697\: \!452\: \!229\: \!299\: \!363\: \!1}}$$

So we get a radius of about 4.70.

Then we use the formula for the volume of a sphere which is 

$${\mathtt{V}} = {\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{3}}}$$

Substituting in R for 4.69........, we get

$${\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{3.14}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{1\,475}}}{{\mathtt{314}}}}\right)}^{{\mathtt{3}}} = {\mathtt{433.965\: \!796\: \!448\: \!807\: \!93}}$$

Rounded to the nearest inch, we get 434 inches cubed.

.............................................

Yes radio made a little mistake.  

Thanks for pointing it out anon but it is no big deal :)

My 3 points to both of you :)

D**n it so close yet so far