A basketball player who has made 70% fould shots during season gets to take 5 shots in the first playoff game. Assuming the shots are independent whats the probability he makes;
exactly 3 of the 5 shots?
Exactly 4
All 5
Atleast 3 of his 5 shots
+23248 These are combinations problems.
Assuming independence, a person who makes 70% of his shots:
Probability of making exactly 3 of 5 shots: 5C3·(0.70)3·(0.30)2 = 10·(0.70)3·(0.30)2 = 0.3087
Probability of making exactly 4 of 5 shots: 5C4·(0.70)4·(0.30)1 = 5·(0.70)4·(0.30)1 = 0.36015
Probability of making all 5 shots: (0.70)5 = 0.16807
Probability of making at least 3 shots: 0.3087 + 0.36015 + 0.16807 = 0.83692
