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a batch of 15 granite slabs is mined, and 4 have defects. If the manager spot checks 3 slabs at random, what is the probability that at least 1 slab is defective?? how do i do this?

 Apr 27, 2015

Best Answer 

 #1
avatar+118723 
+5

P(a least 1 is defective)

 

=1-P(none are defective)

 

$$\\=1-\left(\frac{11}{15}\times \frac{10}{14} \times \frac{9}{13}\right)$$

 Apr 28, 2015
 #1
avatar+118723 
+5
Best Answer

P(a least 1 is defective)

 

=1-P(none are defective)

 

$$\\=1-\left(\frac{11}{15}\times \frac{10}{14} \times \frac{9}{13}\right)$$

Melody Apr 28, 2015

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