A batter hits the baseball 3 feet above the plate at an angle of 35° with an initial velocity of 118.25 ft/sec. The center field wall is 400 feet away and ten feet tall. The baseball clears the wall by how many inches?
+128475 Let's first find out how long it takes to travel 400 ft....this is given by
400 = (118.25)cos(35)t
t = about 4.13 sec
Let y = 0 be the original height....then we would be looking for how many inches it would clear a 7 ft wall
So we have
y = -16(4.13)^2 + 118.25sin(35)(4.13) = 7.2 ft....and this is the heightt in ft at 4.13 sec
So...it clears the all by about .2 ft = 2.4 inches
+128475 Let's first find out how long it takes to travel 400 ft....this is given by
400 = (118.25)cos(35)t
t = about 4.13 sec
Let y = 0 be the original height....then we would be looking for how many inches it would clear a 7 ft wall
So we have
y = -16(4.13)^2 + 118.25sin(35)(4.13) = 7.2 ft....and this is the heightt in ft at 4.13 sec
So...it clears the all by about .2 ft = 2.4 inches
