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A bin has 5 green b***s and $k$ purple b***s in it, where $k$ is an unknown positive integer. A ball is drawn at random from the bin. If a green ball is drawn, the player wins 2 dollars, but if a purple ball is drawn, the player loses 2 dollars. If the expected amount won for playing the game is 50 cents, then what is $k$?

 Apr 25, 2015

Best Answer 

 #1
avatar+33615 
+6

We must have (5*2-k*2)/(5+k) = 0.5   i.e.  (nbr green b***s*$2 + nbr purple b***s(-$2))/(total nbr b***s) = $0.5

 

10 - 2k = (5+k)/2

20 - 4k = 5 + k

15 = 5k

k = 3

 

Three purple b***s

.

 Apr 25, 2015
 #1
avatar+33615 
+6
Best Answer

We must have (5*2-k*2)/(5+k) = 0.5   i.e.  (nbr green b***s*$2 + nbr purple b***s(-$2))/(total nbr b***s) = $0.5

 

10 - 2k = (5+k)/2

20 - 4k = 5 + k

15 = 5k

k = 3

 

Three purple b***s

.

Alan Apr 25, 2015

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