a bird taking a dive follows a path given by the quadratic equation y=2x^2-5x solve the equation to determine the possible values for x when

 

$$\\-3=2x^2-5x\\
0=2x^2-5x+3\\
$multiply to 6, add to -5 numbers are -2 and -3$\\
$change -5x into -2x-3x$\\
0=2x^2-2x-3x+3\\
0=2x(x-1)-3(x-1)\\
0=(2x-3)(x-1)\\
2x-3=0 \qquad or \qquad x-1=0\\
x=3/2\qquad \quad or \qquad x=1\\$$

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