Marcus has two numbers,\(a\) and \(b\). When he divides \(a\) by \(45\) he gets a remainder of \(37\). When he divides \(b\) by \(30\) he gets a remainder of \(9\). What remainder does he get when he divides \(a+b\) by \(15\)?
a/45=N+37/45 b/30=K+9/37 (a+b)/15=what remainder
a (mod45)=37 so a mod15= 7
b(mod30)=9 so b mod 15 = 9
a+b (mod15) = (7+9)mod15 = 1 mod 15