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A board game spinner is divided into three regions labeled $A$$B$ and $C$. The probability of the arrow stopping on region $A$ is $\frac{1}{2}$ and on region $B$ is$\frac{1}{5}$. What is the probability of the arrow stopping on region $C$? Express your answer as a common fraction.

 Apr 16, 2015

Best Answer 

 #1
avatar+130516 
+5

Since the sum of the probabilites = 1, we have

1 - (1/2) - (1/5) =

10/10  - 5/10  - 2/10 = 

3/10      and that's the probability of landing  in region C

 

  

 Apr 16, 2015
 #1
avatar+130516 
+5
Best Answer

Since the sum of the probabilites = 1, we have

1 - (1/2) - (1/5) =

10/10  - 5/10  - 2/10 = 

3/10      and that's the probability of landing  in region C

 

  

CPhill Apr 16, 2015

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