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A box contains 4 white b***s and 5 red b***s. I draw 3 of them out of the box, one at a time, without replacement. What is the probability that the b***s I draw alternate between the two colors?

 Apr 19, 2016
 #1
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The possible draws are

 

W R W  =   (4/9)(5/8)(3/7)  =   5/42      and

 

R W R  =  (5/9) (4/8) (4/7)  =  10/63

 

And the sum of these =

 

5/42 + 10/63  =

 

5/18

 

 

cool cool cool

 Apr 19, 2016

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