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A box contains gold coins.

If the coins are equally divided among six friends, four coins are left over.
If the coins are equally divided among five friends, three coins are left over.

If the box holds the smallest number of coins that meets these two conditions, how many coins are left when equally divided among seven friends?

 

Please explain, with steps.

 Jun 30, 2020
 #1
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You can just 'brute' force it     divide by 6   four coins left over

                 10     16     22     28     34     Divide these by 5 to see leftover (looking for 3)

leftover       0       1      2      

 

So 28 coins    divide by 7    ZERO leftovers

 Jun 30, 2020

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