A box contains gold coins.
If the coins are equally divided among six friends, four coins are left over.
If the coins are equally divided among five friends, three coins are left over.
If the box holds the smallest number of coins that meets these two conditions, how many coins are left when equally divided among seven friends?
Please explain, with steps.
+37170 You can just 'brute' force it divide by 6 four coins left over
10 16 22 28 34 Divide these by 5 to see leftover (looking for 3)
leftover 0 1 2 3
So 28 coins divide by 7 ZERO leftovers
