A car is driven 165 km west and then 95 km southwest. What is the displacement of the car from the point of origin (magnitude and direction)? (physics)
+128460 We have two vectors here, v1 and v2
v1 = <165cos180, 165sin180> and v2 = <95cos(225), 95sin(225)>
Summing the "x" components we have
165cos(180) + 95cos(225) = about -232.18
Summing the "y" components we have
165sin(180) + 95sin(225) = about -67.18
And the magnitude is given by √[(-232.18)2 + (-67.18)2] = about 241.7 km
And the direction is given by
tan-1 (-67.18/-232.18) = about 16.14° in the 3rd quadrant = about 196.14°
+128460 We have two vectors here, v1 and v2
v1 = <165cos180, 165sin180> and v2 = <95cos(225), 95sin(225)>
Summing the "x" components we have
165cos(180) + 95cos(225) = about -232.18
Summing the "y" components we have
165sin(180) + 95sin(225) = about -67.18
And the magnitude is given by √[(-232.18)2 + (-67.18)2] = about 241.7 km
And the direction is given by
tan-1 (-67.18/-232.18) = about 16.14° in the 3rd quadrant = about 196.14°
