A certain class has 6 girls and 5 boys. four of these students are to line up, with two girls on either end and two boys in between, how many such arrangements are possible?
The total arrangements are
Choose one of the girls * Choose one of the boys * Choose one of the remaining boys * Choose one of the remaining girls =
C(6,1) * C(5,1) * C(4,1) * C(5,1) = 6 * 5 * 4 * 5 = 600
