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J.M.J

A circle is inscribed in the ellipse with equation below. A diameter of the circle lies on the minor axis of the ellipse. Find the equation of the circle.

x^2+2y^2=32

 

x^2+y^2= ?

Answering this right is greatly appreciated, God Bless You.

 Mar 4, 2024
edited by Jakelabomb  Mar 4, 2024
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We want the form of the ellipse to be    x^2 / a^2  + y^2 / b^2  = 1

 

x^2 + 2y^2  =  32       divide through by 32

 

x^2 / 32  +  y^2 / 16  =   1

 

b^2   = 16

 

b   =  4 =  semi-minor axis   =   the   radius of the  circle....so r^2 =  16

 

x^2 + y^2  = 16 

 

 

cool cool cool

 Mar 5, 2024

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