+143 a. | 15 nickels, 2 dimes, and 4 quarters | c. | 17 nickels, 3 dimes, and 6 quarters |
b. | 25 nickels, 7 dimes, and 14 quarters | d. | 31 nickels, 5 dimes, and 10 quarters |
+130511 Here's the system we need to solve
5x + 10y + 25z = 545
2y = z → y = z/2
x = z + 11
Substituting........we have
5(z + 11) + 10(z/2) + 25z = 545
5z + 55 + 5z + 25z = 545
35z + 55= 545 subtract 55 from both sides
35z = 490 divide both sides by 35
z = 14 and that's the number of quarters
2y = z → 2y = 14 → y = 7 and thats the number of dimes
x = z + 11 → x = 14 + 11 → x = 25 and that's the number of nickels
+130511 Here's the system we need to solve
5x + 10y + 25z = 545
2y = z → y = z/2
x = z + 11
Substituting........we have
5(z + 11) + 10(z/2) + 25z = 545
5z + 55 + 5z + 25z = 545
35z + 55= 545 subtract 55 from both sides
35z = 490 divide both sides by 35
z = 14 and that's the number of quarters
2y = z → 2y = 14 → y = 7 and thats the number of dimes
x = z + 11 → x = 14 + 11 → x = 25 and that's the number of nickels
