A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°. If a 27-mile-per-hour wind is blowing from a true heading of

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A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°. If a 27-mile-per-hour wind is blowing from a true heading of

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A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°. If a 27-mile-per-hour wind is blowing from a true heading of 120°, determine the velocity and direction of the jet relative to the ground.

A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°.

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Alan · Answer 1 · 2016-11-13T05:05:24

Draw picture:

Use cosine rule to get V (velocity): V^2 = 135^2 + 27^2 - 2*135*27*cos(72)

Use sine rule to get 48 - theta: sin(48 - theta)/27 = sin(72)/V

Hence get theta.

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A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°. If a 27-mile-per-hour wind is blowing from a true heading of

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A commercial passenger jet is flying with an airspeed of 135 miles per hour on a heading of 048°. If a 27-mile-per-hour wind is blowing from a true heading of

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