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A cook has 10 red peppers and 5 green peppers. If the cook selects 8 peppers at random, what is the probability that he selects at least 4 green peppers? Express your answer as a common fraction.

 Nov 20, 2020
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Note....probability of picking any  red  = 10/15  = 2/3

And probability of picking any green = (5/15) = (1/3)

 

P(4 green peppers) =  C(8,4)  ( 2/3)^4 (1/3)^4  =  1120/6561

 

P(5 green peppers)  = C(8, 5)  = (2/3)^3 (1/3)^5  = 560/6561

 

Adding these   ( 1120  + 560) / 6561  = 1680 / 6561   =  560 / 2187

 

cool cool cool

 Nov 20, 2020

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