f(x)=(2x-1)⁵
f'(2)
Using chain rule,
\(\begin{array}{rcl}f(x) &=& (2x - 1)^5\\ f'(x) &=& 5(2x - 1)^4 \dfrac{d}{dx} (2x - 1)\\ &=& 5(2x - 1)^4 (2)\\ &=& 10(2x - 1)^4\\ f'(2) &=& 10(2(2) - 1)^4\\ &=& 810\end{array}\)
