1. Expand (x+2)(x^2 +3)
2. Factor the quadratic x^2 -9x-36
3. Find all values of x that satisfy the equation 3x^2 +14x=5
+1223 1. \((x+2)(x^2+3) = \boxed{x^3 + 2x^2 + 3x + 6}\)
2. \(x^2 - 9x - 36 = \boxed{(x-12)(x+3)}\)
3. \(3x^2 +14x - 5 = 0\)
(quadratic formula)
\(x = {-14 \pm \sqrt{196-4(3)(-5)} \over 2(3)} = {-14 \pm 16 \over 6}\)
\(\boxed{x=-5, -\frac{1}{3}}\)
