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hey! Just a quick (or not) question.

 

if I play 12 games with a 50% of winning each time, what is the probability I will win 10 of these games? 

 

Thanks in advance.

Guest Jul 27, 2018
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I will give this a try!

 

Let total games played =T

Let total games won     =W

Let total games lost       =L

 

T! /[W! x L!] / 2^T ={[12! ] / [10! x 2!]} / [2^12] =

66 / 4,096 =0.01611328125 x 100 =1.61% - probability of winning 10 out of 12 games played.

Guest Jul 27, 2018

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