hey! Just a quick (or not) question.
if I play 12 games with a 50% of winning each time, what is the probability I will win 10 of these games?
Thanks in advance.
I will give this a try!
Let total games played =T
Let total games won =W
Let total games lost =L
T! /[W! x L!] / 2^T ={[12! ] / [10! x 2!]} / [2^12] =
66 / 4,096 =0.01611328125 x 100 =1.61% - probability of winning 10 out of 12 games played.