Given that (2^(1/2))^n = (2^x)/(8^y). Express n in terms of x and y
\(\sqrt{2}^n=\dfrac{2^x}{8^y}\\ 2^{n/2}=2^{x-3y}\\ \dfrac{n}{2}=x-3y\\ n = 2x - 6y\)
