A helicopter takes off from the ground 800 feet from the base of a building. It flies in a straight line directly to the top of the building. If the building is 160 feet tall, what angle did the helicopter take off from? Round the answer to the nearest whole degree.
+33661 The tangent of the take-off angle is height of building/distance from building.
tan(A) = 160/800
A = tan-1(160/800)
$${\mathtt{A}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{160}}}{{\mathtt{800}}}}\right)} \Rightarrow {\mathtt{A}} = {\mathtt{11.309\: \!932\: \!474\: \!02^{\circ}}}$$
So A = 11° to the nearest degree.
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+33661 The tangent of the take-off angle is height of building/distance from building.
tan(A) = 160/800
A = tan-1(160/800)
$${\mathtt{A}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{160}}}{{\mathtt{800}}}}\right)} \Rightarrow {\mathtt{A}} = {\mathtt{11.309\: \!932\: \!474\: \!02^{\circ}}}$$
So A = 11° to the nearest degree.
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