A hill in the Tour de France bike race has a grade of 8%. To the nearest degree, what is the angle that this hill makes with the horizontal ground? Round to the nearest tenth of a degree.
8% means that or every 100 ft of horizontal distance, the hill rises vertically 8 ft. So, 8% = 8/100 = 2/25
So we need to use the inverse tangent to find the angle
tan-1 (2/25) = about 4.57°
