We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
225
1
avatar

A

19​-foot

ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground

5

feet from the base of the building. How high up the wall does the ladder​ reach?

 Feb 25, 2018

Best Answer 

 #1
avatar+18360 
+1

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft     the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

 

a^2 + b^2 = c^2      where c = hypot    a  and b are legs

5^2 + b^2 = 19^2

b^2  = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

 Feb 25, 2018
edited by Guest  Feb 25, 2018
 #1
avatar+18360 
+1
Best Answer

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft     the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

 

a^2 + b^2 = c^2      where c = hypot    a  and b are legs

5^2 + b^2 = 19^2

b^2  = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

ElectricPavlov Feb 25, 2018
edited by Guest  Feb 25, 2018

3 Online Users