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A

19​-foot

ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground

5

feet from the base of the building. How high up the wall does the ladder​ reach?

Guest Feb 25, 2018

Best Answer 

 #1
avatar+12560 
+1

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft     the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

 

a^2 + b^2 = c^2      where c = hypot    a  and b are legs

5^2 + b^2 = 19^2

b^2  = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

ElectricPavlov  Feb 25, 2018
edited by Guest  Feb 25, 2018
 #1
avatar+12560 
+1
Best Answer

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft     the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

 

a^2 + b^2 = c^2      where c = hypot    a  and b are legs

5^2 + b^2 = 19^2

b^2  = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

ElectricPavlov  Feb 25, 2018
edited by Guest  Feb 25, 2018

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