A

19-foot

ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground

5

feet from the base of the building. How high up the wall does the ladder reach?

Guest Feb 25, 2018

#1**+1 **

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

a^2 + b^2 = c^2 where c = hypot a and b are legs

5^2 + b^2 = 19^2

b^2 = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

ElectricPavlov Feb 25, 2018

edited by
Guest
Feb 25, 2018

#1**+1 **

Best Answer

The 19 foot ladder forms the hypotenuse.

One leg is 5 ft the other leg is the side of the wall

Pythagorean theorem (for right triangles ONLY)

a^2 + b^2 = c^2 where c = hypot a and b are legs

5^2 + b^2 = 19^2

b^2 = 19^2 - 5^2

b = height up the wall = sqrt(19^2-5^2) = 18.33 ft

ElectricPavlov Feb 25, 2018

edited by
Guest
Feb 25, 2018