A jet fighter accelerates at 17.1m/s^2 increasing its velocity from 119m/s to 233m/s. How far does it travel in that time?

u=119,   v=233,   a=17.1,   s=?

You need a formula with u,v,a and s    so use [4]

$$\\v^2=u^2+2as\\
233^2=119^2+2*17.1*s\\
233^2-119^2=2*17.1*s\\
(233^2-119^2)/(2*17.1)=s\\$$

$${\frac{\left({{\mathtt{233}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{{\mathtt{119}}}^{{\mathtt{2}}}\right)}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{17.1}}\right)}} = {\frac{{\mathtt{3\,520}}}{{\mathtt{3}}}} = {\mathtt{1\,173.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

displacement = 1173.3 m

Note: you can also do this with calculus. :)

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