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A large lot of items includes 10% defectives.  Thus the chance of selecting a defective item is 0.1 and conversely, the chance of selecting a good item is 0.9. Compute to 4 decimal places, the chance of getting 1 or 2 defectives.  Consider n=10.

Guest Feb 12, 2016
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Probability of selecting 1 defective item from any 10  =

 

C(10,1) * (.10) * (.90)^9  = about .3874

 

Probability of selecting 2 defective items from any 10  =

 

C(10,2) * (.10)^2 * (.90)^8  = about .1937

 

So....the probability of getting 1 OR 2 defectives  =  about  .3874 + .1937  = .5811

 

 

cool cool cool

CPhill  Feb 13, 2016

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