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A light house is located on a small island 3 km away from the nearest point P on a straight shoreline and the light makes 4 revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km away from P?

 Dec 6, 2015
 #1
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A light house is located on a small island 3 km away from the nearest point P on a straight shoreline and the light makes 4 revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km away from P?

 

Distance of light house to new point is  sqrt(9+1)=sqrt10

Circumference of circle with radius of sqrt(10) = 2pi* sqrt(10) 

 

The light is travelling at 4 rvs per minute which is equal to  1 rev per  (1/4) minute

 

so

speed = distance / time

 

\(speed = 2\pi\sqrt{10}\div \frac{1}{4}\;\;km/min\\ speed = 2\pi\sqrt{10}\times 4\;\;km/min\\ speed = 4\pi\sqrt{10}\;\;km/min\\ speed = 4\pi\sqrt{10}\;\;km/min\\ speed \approx 39.73835\;\;km/min\\ speed \approx 39.73835*60\;\;km/hour\\ speed \approx 2384\;\;km/hour\\ \)

 Dec 6, 2015
 #2
avatar+33665 
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Melody has calculated the tangential velocity (that is, the tangent to a circle of radius sqrt(10)).  The component of of this velocity along the (straight) shoreline is obtained by multiplying Melody's velocity by 3/sqrt(10).

 Dec 6, 2015

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