A line is described by the equation $y-4=4(x-8)$. What is the sum of its $x$-intercept and $y$-intercept?

gueesstt
Apr 19, 2018

#1**+2 **

y-4 = 4x-32

y= 4x - 28 when x = 0 you get the y intercept y = -28

when y= 0 you get the x intercept x = 7 Sum = -21

ElectricPavlov
Apr 19, 2018

#2**+1 **

**A line is described by the equation $y-4=4(x-8)$. **

**What is the sum of its $x$-intercept and $y$-intercept?**

\(\begin{array}{|rcll|} \hline y-4 &=& 4(x-8) \\ y-4 &=& 4x-32 \\ 4x-y &=& 32-4 \\ 4x-y &=& 28 \quad & |\quad : 28 \\ \dfrac{x}{7}-\dfrac{y}{28} &=& 1 \\ \dfrac{x}{\mathbf{7}}+\dfrac{y}{\mathbf{-28}} &=& 1 \\\\ \mathbf{7-28} &\mathbf{=}& \mathbf{-21} \\ \hline \end{array} \)

The sum is **-21**

heureka
Apr 19, 2018