We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A line is described by the equation $y-4=4(x-8)$. What is the sum of its $x$-intercept and $y$-intercept?

gueesstt Apr 19, 2018

#1**+2 **

y-4 = 4x-32

y= 4x - 28 when x = 0 you get the y intercept y = -28

when y= 0 you get the x intercept x = 7 Sum = -21

ElectricPavlov Apr 19, 2018

#2**+1 **

**A line is described by the equation $y-4=4(x-8)$. **

**What is the sum of its $x$-intercept and $y$-intercept?**

\(\begin{array}{|rcll|} \hline y-4 &=& 4(x-8) \\ y-4 &=& 4x-32 \\ 4x-y &=& 32-4 \\ 4x-y &=& 28 \quad & |\quad : 28 \\ \dfrac{x}{7}-\dfrac{y}{28} &=& 1 \\ \dfrac{x}{\mathbf{7}}+\dfrac{y}{\mathbf{-28}} &=& 1 \\\\ \mathbf{7-28} &\mathbf{=}& \mathbf{-21} \\ \hline \end{array} \)

The sum is **-21**

heureka Apr 19, 2018