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A line passes through (-2,-3) and has a slope of -3/4 which is an equation of the line?

 

F:  y - 3 = -3/4 (x-2)

G: y + 3 = -3/4 (x-2)

H: y - 3 = -3/4 (x +2)

J: y + 3 = -3/4 (x+2)

 

please explain.

 Jan 4, 2017
 #1
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So a line has the following formula:

 

ax+b

 

a is the slope and b is the point where x = 0.

 

The slope is -3/4

 

so its -3/4 * x + b

 

To get b we just put the point into the equation.

f(x) = -3/4 * x + b

 

-3 = -3/4 * -2 + b   I

 

-3 = 6/4 + b.   I -b I +3

-b = 18/4

b=-4.5

 

Oh wait i didnt read ur answers. 

 

Ayy another edit:

 

y= -3/4 * x - 4.5.  I +3

y+3 = -3/4 * x - 1.5

 

is equal to: 

 

y+3 = -3/4(x+2)

 

Im way to tired but jea no prob.

 Jan 4, 2017
edited by amnesia  Jan 4, 2017
edited by amnesia  Jan 4, 2017
edited by amnesia  Jan 4, 2017
edited by amnesia  Jan 4, 2017
edited by amnesia  Jan 4, 2017
 #2
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Thanks! i didn't really expect anyone to answer

 Jan 4, 2017
 #3
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actually you lost me at | -b|

 Jan 4, 2017
 #4
avatar+259 
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I can try to explain it. Just need to tell me what u didnt understood.

amnesia  Jan 4, 2017

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