A Little Help here?

If this is 3*(x^2)*(y^5)/(9*(x^7)*y) then we have (y^(5-1))/(3*(x^(7-2)) → y^4/(3*x^5)

Edit:

Supposely what you ment was:

3(x^2*(y^5)) / 9x(^7*y)

So the first think you can simplify is 3/9  to 1/3

Now u got both x^something and x^something left.

( x^(2*y^5) ) /( x^ (7y) )

Since they both have the same variable u can take the exponents minus. So u take the first exponent 2*y^5 - 7y

So the end answer is (simplified):

Sry I dont get how to use this codes, but its supposed to be ^-7y....

\(1/3x^(-7 y + 2 y^5)\)