A man has 29 coins in his pocket, all of which are dimes (worth $ 0.10 each) and quarters (worth $ 0.25 each). If the total value of his change is $ 4.85 , how many dimes and how many quarters does he have?
+2234
A man has 29 coins in his pocket, all of which are dimes (worth $ 0.10 each) and quarters (worth $ 0.25 each). If the total value of his change is $ 4.85 , how many dimes and how many quarters does he have?
D = number of Dimes
Q = number of Quarters
D + Q = 29 —>> Q = 29 – D (equation 1)
10D + 25Q = 485 (equation 2)
Substitute (29 – D) in
place of Q in (eq 2) 10D + (25)(29 – D) = 485
10D + 725 – 25D = 485
– 15D = – 240
D = 16
D + Q = 29
16 + Q = 29
Q = 13
.
