A man starts at "O" and wishes to reach a point "P", 200m northeast of "O". If he gets to "P" walking due north first then due east, how far will he have to walk in each direction?
u can use pythagoras theorem. If the long side (north east length) is 200 m, then a squared (north) + b squared (east)=200. But a=b because the guy has to walk as far he goes north as he goes east if its exactly north east.
2a squared= 200 squared
2a squared = 40000
a squared = 20000
a= 141.421356
:)
-SungEun Choi Regents School Pattaya Grade 7 student
u can use pythagoras theorem. If the long side (north east length) is 200 m, then a squared (north) + b squared (east)=200. But a=b because the guy has to walk as far he goes north as he goes east if its exactly north east.
2a squared= 200 squared
2a squared = 40000
a squared = 20000
a= 141.421356
:)
-SungEun Choi Regents School Pattaya Grade 7 student
