A net Force of 160 N East acts on a stationary mass of 15 kg for 0.12 s. What will be the change in Velocity ?

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Guest Apr 27, 2015

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Best Answer

Force = mass*acceleration (F = m*a)

a = 160/15 = 32/3 m/s²

v = u + a*t where u = initial velocity (0), t = time (0.12s), v = final velocity

v = (32/3)*0.12 = 1.28 m/s

(Since the initial velocity was zero, this is the change in velocity).

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Alan Apr 27, 2015

Alan · Answer 1 · 2015-04-27T06:57:00

Force = mass*acceleration (F = m*a)

a = 160/15 = 32/3 m/s²

v = u + a*t where u = initial velocity (0), t = time (0.12s), v = final velocity

v = (32/3)*0.12 = 1.28 m/s

(Since the initial velocity was zero, this is the change in velocity).

.