A number is randomly selected from the first 20 positive integers. What is the probability that it is divisible by 2, 3 or 4? Express your answer as a common fraction.
To figure this problem out, let's first take a look at all the natural numbers up to 20.
The question asks for the probability for a number to be divisible by 2, 3, or 4. However, 2 is a factor of 4, so any number divisible by 4 is already divisible by 4, so there is no need to ever check for divisibility by 2. Also, if you prove a number is divisible by 2, you do not need to check if a number is divisible by 3.Let's take a look:
Natural Numbers from 1-20 | Divisible by 2? | Divisible by 3? | |||||||
1 | |||||||||
2 | ✔ | ||||||||
3 | ✔ | ||||||||
4 | ✔ | ||||||||
5 | |||||||||
6 | ✔ | ✔ | |||||||
7 | |||||||||
8 | ✔ | ||||||||
9 | ✔ | ||||||||
10 | ✔ | ||||||||
11 | |||||||||
12 | ✔ | ✔ | |||||||
13 | |||||||||
14 | ✔ | ||||||||
15 | ✔ | ||||||||
16 | ✔ | ||||||||
17 | |||||||||
18 | ✔ | ✔ | |||||||
19 | |||||||||
20 | ✔ | ||||||||
Now, let's count how many numbers are divisible by either 2 or 3. There are 13 numbers that divisible by either 2 or 3.
Therefore, there is a \(\frac{13}{20}\) chance that a number selected at random from the natural numbers 1 to 20 is divisible by either 2 or 3.
To figure this problem out, let's first take a look at all the natural numbers up to 20.
The question asks for the probability for a number to be divisible by 2, 3, or 4. However, 2 is a factor of 4, so any number divisible by 4 is already divisible by 4, so there is no need to ever check for divisibility by 2. Also, if you prove a number is divisible by 2, you do not need to check if a number is divisible by 3.Let's take a look:
Natural Numbers from 1-20 | Divisible by 2? | Divisible by 3? | |||||||
1 | |||||||||
2 | ✔ | ||||||||
3 | ✔ | ||||||||
4 | ✔ | ||||||||
5 | |||||||||
6 | ✔ | ✔ | |||||||
7 | |||||||||
8 | ✔ | ||||||||
9 | ✔ | ||||||||
10 | ✔ | ||||||||
11 | |||||||||
12 | ✔ | ✔ | |||||||
13 | |||||||||
14 | ✔ | ||||||||
15 | ✔ | ||||||||
16 | ✔ | ||||||||
17 | |||||||||
18 | ✔ | ✔ | |||||||
19 | |||||||||
20 | ✔ | ||||||||
Now, let's count how many numbers are divisible by either 2 or 3. There are 13 numbers that divisible by either 2 or 3.
Therefore, there is a \(\frac{13}{20}\) chance that a number selected at random from the natural numbers 1 to 20 is divisible by either 2 or 3.