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A number n has 3 divisors. How many divisors does $n^3$ have?

 Apr 17, 2021
 #1
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If  a  number  has an odd number of  divisors, it's a perfect square

 

So

 

Let  n  =   a^2

 

Then

 

n^3  =  (a^2)^3   =  a^6

 

The  number of divisors  = (6 + 1)  =   7

 

 

cool cool cool

 Apr 17, 2021

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