A PARALLEL CIRCUIT CONTAINIG THREE RESISTORS OF 1.5 OHMS 4 OHMS AND 12 OHMS IS CONNECTED ACROSS A 10V SUPPLY WHAT IS THE CURRENT FLOWING IN EACH RESISTOR?
Ohm's law says V = I*R where V is voltage across resistance R with current I.
Because the resistors are in parallel, they each have 10Volts across them, so just use Ohm's law on each one:
$$10=I_1*1.5$$
$$I_1=10/1.5$$
$$I_1=6\frac{2}{3}Amps$$
Do the others in a similar way
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