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A positive and a negative charge, each of magnitude 1.7 ✕ 10-5 C, are separated by a distance of 17 cm. Find the magnitude of the force on each of the particles.

physics
 Apr 9, 2015

Best Answer 

 #1
avatar+33661 
+8

Coulomb's law says the force is k*q1*q2/r2 where the q's are the charges, r is the distance between them and k is a constant (k ≈ 8.9876*109 N.m2C-2)

 

$${\mathtt{F}} = {\mathtt{\,-\,}}{\frac{{\left({\mathtt{1.7}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{8.987\: \!6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}}{{{\mathtt{0.17}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{F}} = -{\mathtt{89.876}}$$

 

The force is approximately  -89.9 N

.

 Apr 9, 2015
 #1
avatar+33661 
+8
Best Answer

Coulomb's law says the force is k*q1*q2/r2 where the q's are the charges, r is the distance between them and k is a constant (k ≈ 8.9876*109 N.m2C-2)

 

$${\mathtt{F}} = {\mathtt{\,-\,}}{\frac{{\left({\mathtt{1.7}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{8.987\: \!6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}}{{{\mathtt{0.17}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{F}} = -{\mathtt{89.876}}$$

 

The force is approximately  -89.9 N

.

Alan Apr 9, 2015

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