a projectile stating at 0, is launched at an angle on 10deg. It's max height is 8m. what is its initial magnitude of velocity? Assume no F resistance beside Gravity (a_y) = -9.8m/s^2
+130511 We can use
Hmax = (V0)2 *[sin(Θ)]2 / [2 *(9.8m/s2)]
Where Hmax is the max height, V0 is the original velocity and Θ is the launch angle
So we have
8m = (V0)2 * [sin(10°)]2/ [19.6m/s2]
And rearranging, we have
8m * [19.6m/s2]/[sin(10°)]2 = (V0)2 take the (positive) square root of both sides to solve for V0
V0 = about 72.1 m/s
+130511 We can use
Hmax = (V0)2 *[sin(Θ)]2 / [2 *(9.8m/s2)]
Where Hmax is the max height, V0 is the original velocity and Θ is the launch angle
So we have
8m = (V0)2 * [sin(10°)]2/ [19.6m/s2]
And rearranging, we have
8m * [19.6m/s2]/[sin(10°)]2 = (V0)2 take the (positive) square root of both sides to solve for V0
V0 = about 72.1 m/s
