Let \(x\), \(y\), and \(z\) be real numbers such that
\(\begin{align*} x+y-z &= -8, \\ x-y+z &= 18,\text{ and} \\ -x+y+z &= 30. \\ \end{align*}\)
Compute \(xyz\).
Add the first two equations
2x = 10
x = 5
Add the second two
2z = 48
z = 24
Add the first and third
2y = 22
y = 11
x y z =
5 * 11 * 24 =
1320
Thank you very much, my good sir. Have a great day!
You're welcome !!!!