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avatar+1438 

A regular hexagon has perimeter p and area A. Compute (p^2)/A.

 


Thanks!

 Mar 28, 2018
 #1
avatar+103123 
+1

Call a side,  S

The perimeter  is 6S

The area  = 6* (1/2)S^2 (√3) /2   = 6*(√3/4) *S^2  = (3√3/2)S^2 

 

So  

 

P^2  / A  =    (6S)^2  / [ (√3/3/2) *S^2 ]   =  

 

  36                        72               24

______   =            ___    =       ___    =  8√3

(3√3) /2                3√3              √3

 

 

cool cool cool

 Mar 28, 2018
 #2
avatar+10484 
+1

A regular hexagon has perimeter p and area A. Compute (p^2)/A.

 

laugh

laugh

 Mar 28, 2018
 #3
avatar+1438 
+1

Thanks everyone!

 Mar 28, 2018

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