+4 A rock is thrown into the air. The height (in feet) of the rock after t seconds is given by
h = -16t^2 + 64t
.
Answer the following algebraically
.
a)
What is the height reached by the ball after 1 second
?
________________________
b
)
Determine the maximum height the rock attains
________________________
c
)
How long it will take to reach
maximum height.
________________________
d
)
When does the rock hit the ground?
+36916 When t=1
h= -16(1^2) +64(1) = 48 FT
Max = c- b^2/4a = 0 - (64^2/(4(-16)) = 64 ft
t max 64 = -16t^2 +64t -t^2 +4t -4 = 0 or t^2 -4t+4 = 0 (t-2)(t-2) = 0 so t max = 2 sec
h= 0
0 = -16t^2 + 64t
16t = 64
t= 4 sec
