a s***w gauge has 50 divisions on its circular scale. the pitch of the s***w gauge is 0.5 mm. what is its least count?

The answer to your problem is, 0.01

Step-by-step explanation:

Least count of a s***w gauge is given as,

LC = \({Pitch \over Number..Of..Divisions..On..Circular..Scale}\)

= \( {0.5\over 50}\)

 

= 0.01

 

Thus the answer to your problem is, 0.01