A sample originally contains 24 grams of a radioactive isotope. After 18 days, 18.8 grams of the isotope remains in the sample.

What is the half-life of the isotope?

Guest Jan 13, 2020

#1**+2 **

yf = yo e^{-kt}

18 .8 = 24e^{(-k 18)}

^{k = .0135665}

^{1/2 of 24 is 12 grams remaining at t = 1/2 life}

12= 24e^{-(.051287 t)}

Solve for t = 51.09 days

ElectricPavlov Jan 13, 2020