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A sample originally contains 24 grams of a radioactive isotope. After 18 days, 18.8 grams of the isotope remains in the sample.

What is the half-life of the isotope?

 Jan 13, 2020
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yf = yo e-kt

18 .8 = 24e(-k 18)

 

k = .0135665

 

1/2 of 24 is 12 grams remaining at t = 1/2 life

 

12= 24e-(.051287 t)

 

Solve for t = 51.09 days

 Jan 13, 2020
edited by ElectricPavlov  Jan 13, 2020

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