a school sells 2 sizes of drinks at a football game. a small drink cost $3, a large drink cost $5, the school sold 735 drinks, and made a to

You can use a system of equations to solve this problem.

Let s be small drinks, and l be large drinks.

3s+5l=3125

s+l=735

You can use substitution, elimination, or graphing to solve.

 

Elimination:

3s+5l=3125

To make the l coefficients the same, multiply the bottom equation by 5:

3s+5l=3125

5s+5l=3675

Subtract: -2s=-550.

275 small drinks were sold.

 

Substitution:

3s+5l=3125

s+l=735.

Isolate l on one of the equations: l= 735-s.

Substitute: 3s+(3675-5s.)=3125.

-2s+3675=3125.

-2s=-550

s=275.